某同學(xué)欲配制50g質(zhì)量分?jǐn)?shù)為7.0%的NaCl溶液,在稱量NaCl的操作中,將砝碼放在左盤(1g以下使用游碼).該學(xué)生配制的NaCl溶液的溶質(zhì)的質(zhì)量分?jǐn)?shù)實際是( ?。?br/>A. 5.1%
B. 5.4%
C. 4.8%
D. 5.0%
由左盤的質(zhì)量=右盤的質(zhì)量+游碼的質(zhì)量可知:砝碼質(zhì)量=物體質(zhì)量+游碼的質(zhì)量,所以物體質(zhì)量=砝碼質(zhì)量-游碼質(zhì)量,即:物體質(zhì)量=3 g-0.5 g=2.5 g.所以該學(xué)生配制的NaCl溶液的溶質(zhì)的質(zhì)量分?jǐn)?shù)為:
×100%=5.1%.
故選A.