為了得到函數(shù)y=sin(2x-π/6)的圖像,可以將函數(shù)y=cos2x的圖像向右平移π/3的個單位
y=cos2(x-π/3)=cos(2x-2π/3)=cos[(2x-π/6) -π/2]=cos[π/2 -(2x-π/6)]=sin(2x-π/6).
希望我的回答能夠幫到你,順祝愉快!答案是左移π/6，是不是答案錯了..如果是左移π/6y=cos[2(x+π/6)]=cos(2x+π/3)=cos(2x+5π/6-π/2)=cos[π/2-(2x+5π/6)]=cos(2x+5π/6)=cos(2x+π/6-π)=cos[π-(2x+π/6)]=-cos(2x+π/6) ≠ sin(2x-π/6) 所以答案有誤！