精品偷拍一区二区三区,亚洲精品永久 码,亚洲综合日韩精品欧美国产,亚洲国产日韩a在线亚洲

  • <center id="usuqs"></center>
  • 
    
  • 化簡 1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x)-3)(x-4)+…+1/(x-9)(x-

    化簡 1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x)-3)(x-4)+…+1/(x-9)(x-
    必須回答
    數(shù)學(xué)人氣:826 ℃時(shí)間:2020-10-02 02:41:26
    優(yōu)質(zhì)解答
    1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x)-3)(x-4)+…+1/(x-9)(x-10)=-[1/(x-1)-1/(x-2)+1/(x-2)-1/(x-3)+.+1/1/(x-9)-1/(x-10)]=-[1/(x-1)-1/(x-10)]=-[(x-10)-(x-1)]/[(x-10)-(x-1)]=-(-9)/(x^2-11x+10)...
    我來回答
    類似推薦
    請使用1024x768 IE6.0或更高版本瀏覽器瀏覽本站點(diǎn),以保證最佳閱讀效果。本頁提供作業(yè)小助手,一起搜作業(yè)以及作業(yè)好幫手最新版!
    版權(quán)所有 CopyRight © 2012-2024 作業(yè)小助手 All Rights Reserved. 手機(jī)版