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  • 6道數(shù)學因式分解

    6道數(shù)學因式分解
    (1)2x(x-y)四次方-x²(x-y)²+xy(y-x)²
    (2)8a三次方-b三次方
    (3)4(x-y+1)+y(y-2x)
    (4)3x²+5xy-2y²+x+9y+4
    (5)2x²+xy-y²-4x+5y-6
    (6)3x²+4xy-y²
    數(shù)學人氣:628 ℃時間:2020-06-26 02:49:58
    優(yōu)質(zhì)解答
    (1)
    2x(x-y)^4-x²(x-y)²+xy(y-x)²
    =x(x-y)²[2(x-y)²-x+y]
    =x(x-y)²[2(x-y)²-(x-y)]
    =x(x-y)²(x-y)[2(x-y)-1]
    =x(x-y)³(2x-2y-1)
    (2)
    8a³-b³
    =(2a)³-b³
    =(2a-b)(4a²+2ab+b²)
    (3)
    (x-y+1)+y(y-2x)
    =4x-4y+4+y²-2xy
    =(y-2)²-2x(y-2)
    =(y-2)(y-2-2x)
    (4)
    3x²+5xy-2y²+x+9y-4【題有誤,最后一項應(yīng)該是-4而不是+4,若被猜對請往下看】
    3x²+x(5y+1)-(2y²-9y+4)
    =3x²+x(5y+1)-(2y-1)(y-4)
    =[3x-(y-4)][x+(2y-1)]
    =(3x-y+4)(x+2y-1)
    (5)
    2x²+xy-y²-4x+5y-6
    =2x²+(y-4)x+(-y2+5y-6)
    =2x²+(y-4)x+[-(y2-5y+6)]
    =2x²+(y-4)x+[-(y-2)(y-3)]
    =[1x+(y-3)][2x+(-y+2)]
    =(x+y-3)(2x-y+2)
    (6)
    3x²-4xy+y²【題目有誤,應(yīng)該是+y²,-y²的話無法分解,若猜對的話請往下看】
    =(3x-y)(x-y)
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