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  • 六年級簡便運算

    六年級簡便運算
    17/9÷[(4/9+1/2)×9/17]
    =
    1又2/3×1又2/5×1又2/7×1又2/9×1又2/11×…×1又2/199
    =
    (1+1/3+1/5+1/10+1/15+1/30)÷(1/2+1/4+1/6+1/12+1/20+1/60)
    =
    [17.1-17.2÷(3.1-0.7)]×0.6
    =
    (2又2/9×4/5+2又2/9×6.2-5.8×2又2/9-1/5÷9/20)×9/20
    =
    2009÷2009又2009/2010+1/2011
    =
    要過程!多謝了!
    數(shù)學(xué)人氣:880 ℃時間:2020-01-25 10:42:52
    優(yōu)質(zhì)解答
    17/9÷[(4/9+1/2)×9/17]
    =17/9÷(17/18*9/17)
    =(17/9)*2
    =34/9
    1又2/3×1又2/5×1又2/7×1又2/9×1又2/11×…×1又2/199
    =5/3*7/5*9/7*.199/197*201/199
    =201/3
    =67
    (1+1/3+1/5+1/10+1/15+1/30)÷(1/2+1/4+1/6+1/12+1/20+1/60)
    =[(30+10+6+3+2+1)/30]÷[(30+15+10+5+3+1)/60]
    =(52/30)*(60/64)
    =13/8
    [17.1-17.2÷(3.1-0.7)]×0.6
    =(17.1-17.2÷2.4)*0.6
    =17.1*0.6-17.2/2.4*0.6
    =10.26-4.3
    =5.94
    (2又2/9×4/5+2又2/9×6.2-5.8×2又2/9-1/5÷9/20)×9/20
    =20/9*(0.8+6.2-5.8-0.2)*9/20
    =0.8+6.2-5.8-0.2
    =7-6
    =1
    2009÷2009又2009/2010+1/2011
    =2009÷[2009*(1+1/2010)]+1/2011
    =1÷(2011/2010)+1/2011
    =2010/2011+1/2011
    =1
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