(2x+1)/5-(x+1)/3=0 兩邊同時(shí)乘以15得
3(2x+1)-5(x+1)=0
6x+3-5x-5=0
x-2=0
x=2沒看懂哦(2x+1)/5-(x+1)/3=0去分母3(2x+1)-5(x+1)=0去括號(hào)6x+3-5x-5=0合并同類項(xiàng)x-2=0 移項(xiàng)x=2
(2x+1)/5-(x+1)/3=0
(2x+1)/5-(x+1)/3=0
數(shù)學(xué)人氣:742 ℃時(shí)間:2020-04-11 16:35:10
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