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  • AP chemistry的一道題目

    AP chemistry的一道題目
    Step 1:N2H2O2  N2HO2- + H+ (fast equilibrium)
    Step 2:N2HO2-  N2O + OH- (slow)
    Step 3:H+ + OH-  H2O (fast)
    Nitramide,N2H2O2,decomposes slowly in aqueous solution.This decomposition is believed to occur according to the reaction mechanism above.The rate law for the decomposition of nitramide that is consistent with this mechanism is given by which of the following?
    (A) Rate= k[N2H2O2]
    (B) Rate= k[N2H2O2][H+]
    (C) Rate= k[N2H2O2]/[H+]
    (D) Rate= k[N2H2O2]/[N2HO2-]
    (E) Rate= k[N2H2O2][OH-]
    Answer:C
    請(qǐng)具體講一講為什么選C啊?
    英語(yǔ)人氣:817 ℃時(shí)間:2020-07-02 17:43:27
    優(yōu)質(zhì)解答
    The rate law is determined in this case by the slowest reaction step:
    rate = k[N2HO2-]
    Equilibrium for step before the slowest step:
    K = [N2HO2-][H+] / [N2H2O2]
    K[N2H2O2] / [H+] = [N2HO2-]
    rate = k{K[N2H2O2] / [H+]}
    rate = (k1)[N2H2O2] / [H+]
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