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  • (-1/3a^2b^2)^2(-2ab^2)^3÷(1/9a^4b^4)^3 [(x+y)^2-(x+y)(x+y)]÷2y

    (-1/3a^2b^2)^2(-2ab^2)^3÷(1/9a^4b^4)^3 [(x+y)^2-(x+y)(x+y)]÷2y
    (-1/3a^2b^2)^2(-2ab^2)^3÷(1/9a^4b^4)^3
    [(x+y)^2-(x+y)(x+y)]÷2y
    因式分解:
    x^3y-6x^2y^2+9xy^3
    (a^2+4b^2)2-16a^2b^2
    數(shù)學(xué)人氣:353 ℃時(shí)間:2019-10-11 20:22:12
    優(yōu)質(zhì)解答
    (-1/3a^2b^2)^2(-2ab^2)^3÷(1/9a^4b^4)^3
    =1/9a^4b^4×(-8a³b^6)÷(1/729的12次方b的12次方)
    =-648/a的5次方b²
    [(x+y)^2-(x+y)(x+y)]÷2y
    =0÷2y
    =0
    x^3y-6x^2y^2+9xy^3
    =xy(x²-6xy+9y²)
    =xy(x-3y)²
    (a^2+4b^2)2-16a^2b^2
    =(a²+4b²+4ab)(a²+4b²-4ab)
    =(a+2b)²(a-2b)²
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