K2Cr2O7+4H2SO4+3K2SO3=4K2SO4+Cr2(SO4)3+4H2O
11P+15CuSO4+24H2O=6H3PO4+5Cu3P+15H2SO4
K2Cr2O7+H2SO4+K2SO3=K2SO4+Cr2(SO4)3+H2O
K2Cr2O7+H2SO4+K2SO3=K2SO4+Cr2(SO4)3+H2O
P+CuSO4+H2O=H3PO4+Cu3P+H2SO4
請將以上兩個方程式配平
謝謝o(∩_∩)o
P+CuSO4+H2O=H3PO4+Cu3P+H2SO4
請將以上兩個方程式配平
謝謝o(∩_∩)o
數(shù)學人氣:232 ℃時間:2020-03-22 11:55:47
優(yōu)質(zhì)解答
我來回答
類似推薦
- K2Cr2O7+CH3CH2OH+H2SO4--Cr2(SO4)3+CH3COOH+K2SO4+H2O
- _K2Cr2O7+_H2SO4+_FeSO4=>_Fe2(SO4)3+_K2SO4+_Cr2(SO4)3+_H2O
- 配平K2Cr2O7+KI+H2SO4---K2SO4+I2+Cr2(SO4)3+H2O
- 配平 k2cr2o7 + ki + h2so4---k2so4+ cr2(so4)3+ i2+ h2o
- C+K2Cr2O7+H2SO4=CO2+K2SO4+Cr2(SO4)3+H2O怎么配平?
- 已知實數(shù)x,y滿足2x+3y≤14,2x+y≤9,x≥0,y≥0,S=3x+ay,若S取得最大值時的最優(yōu)解有無窮多個,則實數(shù)a=?
- 請問這種成分還屬301不銹鋼嗎?(C-0.1003;Si-0.2467;Mn-2.2387;p-0.358;S-0.169;Cr-14.6342;Ni-6.0215)
- X=2*3*5*7*11*13*17*19*23*29*.N(N為質(zhì)數(shù)),求證:X+1為質(zhì)數(shù)
- 若√2007n是個非零整數(shù),則最小整數(shù)n是?
- Either I or he ( )soccer with Tom 四個選項 play are plays is
- .the music festival was great!Many famous people (attended) it.
- 如果(M)表示m的全部因數(shù)的和,如(4)=1+2+4=7,則(18)-(21)=()