解
4a²-(b-c)²
=(2a)²-(b-c)²
=[2a-(b-c)][2a+(b-c)]
=(2a-b+c)(2a+b-c)
3(a+b)-27c²
=3[(a+b)-9c²}
=3(a+b-9c²)
x²(x-y)-4(y-x)²
=x²(x-y)-4(x-y)²
=(x-y)[x²-4(x-y)]
=(x-y)(x²-4x-4y)
分解因式 (1)4a²-(b-c)²(2)3(a+b)-27c²(3)x²(x-y)-4(y-x)²
分解因式 (1)4a²-(b-c)²(2)3(a+b)-27c²(3)x²(x-y)-4(y-x)²
數(shù)學人氣：664 ℃時間：2020-08-27 03:53:42
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