│X-Y+2│+√2x-3y-2+z^2 -4z+4
=│X-Y+2│+√2x-3y-2+(z-2)^2
=0
x-y+2=0
2x-3y-2=0
z=2
解方程組得：
x=-8,y=-6,z=2
4x-3√y+√z^2沒有意義
---------------題目錯了
已知實數(shù)X、Y、Z滿足│X-Y+2│+√2x-3y-2+z^2 -4z+4=0,求4x-3√y+√z^2的值.
已知實數(shù)X、Y、Z滿足│X-Y+2│+√2x-3y-2+z^2 -4z+4=0,求4x-3√y+√z^2的值.
數(shù)學人氣：358 ℃時間：2020-03-20 04:23:39
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