Na2CO3+BaCl2=BaCO3↓+2NaCl
106 197 117
x 39.4g y
∴
106 |
197 |
x |
39.4g |
197 |
117 |
39.4g |
y |
解之得:x=21.2g,y=23.4g;
(2)所得濾液中溶質的質量分數(shù)為:
22.8g?21.2g+23.4g |
22.8g+350g+166.6g?39.4g |
25g |
500g |
答:(1)原樣品中的碳酸鈉的質量為21.2g;
(2)最后所得濾液中溶質的質量分數(shù)為5%.
106 |
197 |
x |
39.4g |
197 |
117 |
39.4g |
y |
22.8g?21.2g+23.4g |
22.8g+350g+166.6g?39.4g |
25g |
500g |