在平面直角坐標(biāo)系中,入射光線經(jīng)過(guò)y軸上點(diǎn)A(0,3),由x軸上點(diǎn)C反射,反射光線經(jīng)過(guò)點(diǎn)B(-3,1),則點(diǎn)C的坐標(biāo)為_(kāi)_____.
![](http://hiphotos.baidu.com/zhidao/pic/item/ae51f3deb48f8c543ba6119e39292df5e0fe7f0e.jpg)
A(0,3)關(guān)于x軸的對(duì)稱點(diǎn)的坐標(biāo)是(0,-3),
設(shè)經(jīng)過(guò)B,與(0,-3)的函數(shù)解析式是y=kx+b,
根據(jù)待定系數(shù)法,就可以求出函數(shù)解析式是y=-
x-3,
令y=0,解得x=-
.
因而點(diǎn)C的坐標(biāo)為(-
,0).