已知x+y+13-4倍根號x-6倍根號y=0,求實數(shù)x,y的值?
已知x+y+13-4倍根號x-6倍根號y=0,求實數(shù)x,y的值?
數(shù)學人氣：692 ℃時間：2020-03-24 19:40:48
優(yōu)質(zhì)解答
思路：已知x+y+13-4倍根號x-6倍根號y=0 你可以將上述條件變形,即： x－4√x＋4＋y－6√y＋9=0 仔細觀察,x－4√x＋4可以配方成：﹙√x－2﹚,y－6√y＋9可以配方成：﹙√y－3﹚ 所以 ﹙√x－2﹚＋﹙√y－3﹚=0 剩下...
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