2x4-x3-6x2-x+2
=x^2(2x^2-x-6)-(x-2)
=x^2(2x+3)(x-2)-(x-2)
=(x-2)[x^2(2x+3)-1]
=(x-2)(2x^3+3x^2-1)
=(x-2)[(2x^3+2x^2)+(x^2-1)]
=(x-2)[2x^2(x+1)+(x+1)(x-1)]
=(x-2)(x+1)(2x^2+x-1)
=(x-2)(x+1)(2x-1)(x+1)
=(x+1)^2(x-2)(2x-1)最后是-6不是—2額，，，不好意思啊，我看錯(cuò)了。實(shí)在抱歉沒(méi)關(guān)系，可以解答此題嗎可以，稍等啊可以手寫(xiě)給你嗎2x4-x3-6x2-x-6
=x^2(2x^2-x-6)-(x+6)
=x^2[(2x^2)-(x+6)]-(x+6)很晚了，先給你劃到這。給你個(gè)思路謝謝了！