為隱函數(shù)微分1)y=x+e^ydy=dx+e^ydydy/dx=1/(1-e^y)2)y=cos(xy)-xdy=-sin(xy)(ydx+xdy)-dxdy=-[sin(xy)*y+1]dx-sin(xy)*xdy[1+xsin(xy)]dy=-[ysin(xy)+1]dxdy/dx=-[ysin(xy)+1]/[xsin(xy)+1]第二題和答案一樣,第一題答案上寫的是dy/dx=e^y/1-xe^y答案錯(cuò)了?你再看看抄錯(cuò)題沒有，否則就是那習(xí)題答案錯(cuò)了。