設(shè)3^x=4^y=6^z=k,
1/Log[6,k]-1/Log[3,k]=Log[k,6]-Log[k,3]=Log[k,2]=1/Log[2,k]=1/Log[4,k^2]=1/(Log[4,k])=1/(2y)
一道關(guān)于數(shù)學(xué)對(duì)數(shù)的題目.
一道關(guān)于數(shù)學(xué)對(duì)數(shù)的題目.
設(shè)3^x=4^y=6^z,求證：1/z - 1/x =1/2y
設(shè)3^x=4^y=6^z,求證：1/z - 1/x =1/2y
數(shù)學(xué)人氣：642 ℃時(shí)間：2020-03-26 21:53:41
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