令x = a * tanz,dx = a * sec²z dz
sinz = x/√(a² + x²),cscz = √(a² + x²)/x,cotz = 1/tanz = a/x
∫ dx/[x√(a² + x²)]
= ∫ 1/[(a * tanz) * |a * secz|] * (a * sec²z dz)
= (1/a)∫ cscz dz
= (1/a)ln|cscz - cotz| + C
= (1/a)ln|√(a² + x²)/x - a/x| + C
= (1/a)ln| [√(a² + x²) - a]/x | + C若改為x2-a2呢?令x = a * secz,dx = a * secztanz dz
∫ dx/x根號(hào)(a2+x2)積分怎么求
∫ dx/x根號(hào)(a2+x2)積分怎么求
數(shù)學(xué)人氣:654 ℃時(shí)間:2020-04-04 10:00:15
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