matlab方程數(shù)大于未知數(shù)個(gè)數(shù)時(shí)的求解
syms xn yn zn xt yt zt
[o3,o4,o5,o6]=solve('cos(o3)*cos(o4)*cos(o5)-sin(o3)*sin(o5)=xn','cos(o3)*cos(o4)*cos(o5)+cos(o3)*sin(o5)=yn','-sin(o4)*cos(o5)=zn','(-cos(o3)*cos(o4)*sin(o5)-sin(o3)*cos(o5))*cos(o6)+cos(o3)*sin(o4)*sin(o6)=xt','(-sin(o3)*cos(o4)*sin(o5)+cos(o3)*cos(o5))*cos(o6)+sin(o3)*sin(o4)*sin(o6)=yt','sin(o4)*sin(o5)*cos(o6)+cos(o4)*sin(o6)=zt','o3,o4,o5,o6')
古道熱腸,路過(guò)有知情者望不吝賜教!
我把原來(lái)六個(gè)方程化簡(jiǎn),約掉兩個(gè),輸入到matlab里仍然解不出來(lái),化簡(jiǎn)后的方程組如下：
syms xn yn zn xt yt zt
[o3,o4,o5,o6]=solve('xn*cos(o3)+yn*sin(o3)=cos(o4)*cos(o5)','-sin(o4)*cos(o5)=zn','xt*cos(o3)+yt*sin(o3)=sin(o4)*sin(o6)-cos(o4)*sin(o5)*cos(o6)','sin(o4)*sin(o5)*cos(o6)+cos(o4)*sin(o6)=zt','o3,o4,o5,o6')