6x2-2mxy-2y2+4xy-5x+2=6x2+(4-2m)xy-2y2-5x+2,
∵結(jié)果中不含xy項,
∴4-2m=0,
解得:m=2,
-m3-2m2-m+1-m3-m+2m2+5=-2m3-2m+6,
當(dāng)m=2時,原式=-2×8-2×2+6=-14.
如果滿意請采納為滿意答案哦~
謝謝!
6x2-2mxy-2y2+4xy-5x+2=6x2+(4-2m)xy-2y2-5x+2,
∵結(jié)果中不含xy項,
∴4-2m=0,
解得:m=2,
-m3-2m2-m+1-m3-m+2m2+5=-2m3-2m+6,
當(dāng)m=2時,原式=-2×8-2×2+6=-14.
如果滿意請采納為滿意答案哦~
謝謝!