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  • 計(jì)算2m/5n²p-3n/4mp²

    計(jì)算2m/5n²p-3n/4mp²
    還有兩題:3y/2x+2y+2xy/x²+xy
    2x/x²-64y²-1/x-8y
    就這三題,做起來有很多疑問。
    數(shù)學(xué)人氣:487 ℃時(shí)間:2020-03-25 05:36:46
    優(yōu)質(zhì)解答
    2m/5n²p-3n/4mp²=(8m²p-15n³)/20mn²p²3y/2x+2y+2xy/x²+xy=3y/2(x+y)+2xy/x(x+y)=3y/2(x+y)+2y/(x+y)=(3y+4y)/2(x+y)=7y/(2x+2y) 2x/x²-64y²-1/x-8y=2x/(x-8y)(x+8y)-1...3y/2x+2y+2xy/x²+xy這題我有不明白的,=3y/2(x+y)+2y/(x+y)=(3y+4y)/2(x+y)為什么3y加4y不是加2y的么3y/2x+2y+2xy/x²+xy=3y/2(x+y)+2xy/x(x+y)=3y/2(x+y)+2y/(x+y)=3y/2(x+y)+4y/2(x+y)=(3y+4y)/2(x+y)=7y/(2x+2y)還有一個(gè)疑問2x/x²-64y²-1/x-8y: =2x/(x-8y)(x+8y)-1/(x-8y) =(2x-x-8y)/(x-8y)(x+8y)不是(2x-1)的么為什么是(2x-x-8y)別怪我差,我實(shí)在是亂。呵呵,用點(diǎn)心讀書。 2x/x²-64y²-1/x-8y=2x/(x-8y)(x+8y)-1/(x-8y)=2x/(x-8y)(x+8y)-(x+8y)/(x-8y)(x+8y)=(2x-x-8y)/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)最后一個(gè)問題歐,就是=(2x-x-8y)/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)2x怎消去的=2x-x-8y=x-8y
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