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  • 已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)

    已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)
    數(shù)學(xué)人氣:877 ℃時(shí)間:2019-08-22 13:26:06
    優(yōu)質(zhì)解答
    (3a-b)/(2b-a)=7,
    3a-b=7(2b-a),
    2a=3b
    (ax+y)/(2x-y)=5,
    x+y=5(2x-y),
    3x=2y
    (3ax-by)/(ax+2by),通過(guò)分子和分母同乘以6,
    =6(3ax-by)/6(ax+2by)
    =(18ax-6by)/(6ax+12by)
    =(3*2a*3x-6by)/(2a*3x+12by)
    =(3*3b*2y-6by)/(3b*2y+12by)
    =(18by-6by)/(6by+12by)
    =12by/18by
    =2/3
    或(3a-b)/(2b-a)=7,
    3a-b=7(2b-a),
    2a=3b.1
    (ax+y)/(2x-y)=5,
    x+y=5(2x-y),
    3x=2y.2
    1式*2式得
    6ax=6by
    ax=by
    (3ax-by)/(ax+2by)
    =(3by-by)/(by+2by)
    =2by/3by
    =2/3
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