lim n→∞ an^2+bn+1/3n-2
=lim n→∞ ( an + b + 1/n )/ (3-2/n)
∴ a = 0
lim n→∞ an^2+bn+1/3n-2
= lim n→∞ bn+1/3n-2
= lim n→∞ [b + 1/n]/[3-2/n]
= b/3 = -2
∴ b = -6
lim n→∞ an^2+bn+1/3n-2=-2,求a,b之值
lim n→∞ an^2+bn+1/3n-2=-2,求a,b之值
數(shù)學(xué)人氣：796 ℃時間：2020-04-07 00:53:28
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