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  • 求值:2sin50°+cos10°*(1+根號3tan10°)/cs35°cos40°+cos50°cos55°

    求值:2sin50°+cos10°*(1+根號3tan10°)/cs35°cos40°+cos50°cos55°
    是cos35° 不好意思。打錯了
    數(shù)學人氣:356 ℃時間:2020-03-24 13:54:53
    優(yōu)質(zhì)解答
    原式的分子部分=2sin50° + cos10° + √3cos10°×[(sin10°)/(cos10°)]
    =2sin50° + cos10° + √3sin10°
    =2sin50° + 2[(1/2)cos10° + (√3/2)sin10°]
    =2sin50° + 2sin(10°+ 30°)
    =2sin50° + 2sin40°
    =2sin[(50°+40°)/2]cos[(50°-40°)/2]
    =2sin45°×cos5°
    =√2cos5°
    原式的分母部分=(1/2)[cos(35°+40°) + cos(35°-40°)] + (1/2)[cos(50°+55°) + cos(50°-55°)]
    =(1/2)[cos75° + cos(-5°)] + (1/2)[cos105° + cos(-5°)]
    =(1/2)cos75° + (1/2)cos5° + (1/2)cos105° + (1/2)cos5°
    =(1/2)(cos75° + cos105°) + cos5°
    =(1/2){2cos[(75°+105°)/2]cos[(75°-105°)/2]} + cos5°
    =cos90°cos(-15°) + cos5°
    =cos5°
    整理后得:=(√2cos5°)/(cos5°) =√2
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