n(H2)=5.6L/22.4Lmol-1=0.25mol
Mg+2HCl=MgCl2+H2
2Al+6HCl=2AlCl3+3H2
鎂鋁合金的質(zhì)量
m(合金)=n(Mg)*24gmol-1+n(Al)*27gmol-1=5.1g
生成H2物質(zhì)的量
n(H2)=n(Mg)+1.5n(Al)=0.25mol
兩式聯(lián)立,解得
n(Mg)=0.1mol,n(Al)=0.1mol
鎂的質(zhì)量m(Mg)=24gmol-1*0.1mol=2.4g
鋁的質(zhì)量m(Al)=27gmol-1*0.1mol=2.7g
鹽酸的物質(zhì)的量n(HCl)=2n(Mg)+3n(Al)=0.5mol
鹽酸的物質(zhì)的量濃度
c(HCl)=0.5mol/100mL=5mol/L