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  • 化簡求值1/(x+1)-[(x+3)/(x^2-1)] / [(x^2+4x+3)/(x^2-2x+1)]其中x=-3

    化簡求值1/(x+1)-[(x+3)/(x^2-1)] / [(x^2+4x+3)/(x^2-2x+1)]其中x=-3
    2.已知a/b=2/7,求[49(a^4) -4(b^4)] / [7(a^3)b + 2a(b^3)]的值.以上
    數(shù)學(xué)人氣:327 ℃時間:2020-06-02 01:54:55
    優(yōu)質(zhì)解答
    1.1/(x+1)-[(x+3)/(x^2-1)] / [(x^2+4x+3)/(x^2-2x+1)]
    =1/(x+1)-{(x+3)/[(x-1)(x+1)]} / {[(x+1)(x+3)]/[(x-1)^2]}
    =1/(x+1)-{(x+3)[(x-1)^2]}/[(x-1)(x+1)^2(x+3)]
    =1/(x+1)-(x-1)/[(x+1)^2]
    =(x+1)/[(x+1)^2]-(x-1)/[(x+1)^2]
    =2/[(x+1)^2]
    =2/[(-3+1)^2]
    =1/2
    2.[49(a^4) -4(b^4)] / [7(a^3)b + 2a(b^3)]
    ={[7(a^2) -2(b^2)][7(a^2) +2(b^2)]} / {[7(a^2) + 2(b^2)]ab}
    =[7(a^2) -2(b^2)]/ (ab)
    =7(a/b) -2(b/a)
    =7*(2/7)-2*(7/2)
    =2-7
    =-5
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