y=1+xe^y==>y'=(1+xe^y )'
==>y'=(xe^y)'
==>y'=1*e^y+xe^y*y'
==>y'(1-xe^y)=e^y
==>y'=e^y/(1-xe^y)
因為y=1+xe^y,則1-xe^y=2-y,得y'=e^y/(2-y)
即dy/dx=e^y/(2-y)

dy/dx=e^y/(2-y)
==>d(dy/dx)/dx=d(e^y/(2-y))
==>d(dy/dx)/dx=[e^y*dy*(2-y)-e^y*(-dy)]/(2-y)^2
因為dy/dx=e^y/(2-y),則
==>d(dy/dx)/dx=[e^2y+e^2y/(2-y)]/(2-y)^2
==>d(dy/dx)/dx=e^2y[1+1/(2-y)]/(2-y)^2
求二階導數是對一階導數直接再次求導,可用d(dy/dx)/dx這個公式
dx是微分變量==>y'(1-xe^y)=e^y這一步什么意思？？可以解析下媽？？(*^__^*) 嘻嘻……