x=(x^2-4x+2)/√(x^2-8x+12)
x√(x^2-8x+12)=(x^2-4x+2)
x^2(x^2-8x+12)=(x^2-4x+2)^2
x^4-8x^3+12x^2=x^4+16x^2+4-8x^3+4x^2- 16x
12x^2=16x^2+4+4x^2- 16x
8x^2+4- 16x =0
2x^2- 4x +1=0
x=(4±√16- 8)/ 4
x=(2±√2 ) /2
x1=(2+√2 ) /2 , x2=(2- √2 ) /2
x=x^2-4x+2除以根號(hào)x^2-8x+12
x=x^2-4x+2除以根號(hào)x^2-8x+12
其他人氣：940 ℃時(shí)間：2020-06-03 09:31:02
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