3a 2a-1 7a-8這個是3個連續(xù)的數(shù)
則
2(2a-1)=3a+7a-8
4a-2=10a-8
a=1
數(shù)列.求a是多少.3a 2a-1 7a-8這個是3個連續(xù)的數(shù)
數(shù)列.求a是多少.3a 2a-1 7a-8這個是3個連續(xù)的數(shù)
數(shù)學(xué)人氣：993 ℃時間：2020-10-01 11:15:32
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