1.
①Mg+2HCl=H2↑+MgCl2
```24``````````2
②Zn+2HCl=H2↑+ZnCl2
```65``````````2
③Fe+2HCl=H2↑+FeCl2
```56``````````2
因此當(dāng)鹽酸足量時,①生成氫氣質(zhì)量30g/24×2=2.5g,②生成氫氣質(zhì)量30g/65*2≈0.923g,③生成氫氣質(zhì)量30g/56*2≈1.07g;
當(dāng)生成氫氣30g時,①需金屬30g/2*24=360g,②需金屬30g/2*65=975g,③需金屬30g/2*56=840g
2.
設(shè)理論上可日產(chǎn)含鐵98%的生鐵的質(zhì)量是x
98%x=5000t×76%(2Fe/Fe2O3)=5000t×76%×0.7
解得x≈2714.29t
【等號左面是產(chǎn)的生鐵中Fe質(zhì)量,等號右邊是礦石中Fe質(zhì)量,元素質(zhì)量守恒】
3.設(shè)需要含F(xiàn)e3O4的90%磁鐵礦石的質(zhì)量是
2000t×(1-3%)=90%x×(3Fe/Fe3O4)=90%x×(21/29)
解得x≈2976.72t
【等號左面是產(chǎn)的生鐵中Fe質(zhì)量,等號右邊是礦石中Fe質(zhì)量,元素質(zhì)量守恒】