∵e^x = Σ x^n / n!
∴e^(-x) = Σ (-x)^n / n!
f(x) = [e^x +e^(-x)] / 2
= Σ x^(2k) / (2k)!
【n為奇數(shù)的項(xiàng)都抵消了】
講函數(shù)f（x）=（e^x+e^-x）/2展開成x的冪級(jí)數(shù)
講函數(shù)f（x）=（e^x+e^-x）/2展開成x的冪級(jí)數(shù)
數(shù)學(xué)人氣：816 ℃時(shí)間：2020-02-05 05:21:10
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