設(shè)長(zhǎng)半軸長(zhǎng)為a,短半軸長(zhǎng)為b,半焦距為c,
則近地點(diǎn)A距地心為a-c,遠(yuǎn)地點(diǎn)B距地心為a+c.
∴a-c=m+R,a+c=n+R,
∴a=
m+n |
2 |
n?m |
2 |
又∵b2=a2-c2=(
m+n |
2 |
n?m |
2 |
∴b=
(m+R)(n+R) |
∴短軸長(zhǎng)為2b=2
(m+R)(n+R) |
故答案為:2
(m+R)(n+R) |
m+n |
2 |
n?m |
2 |
m+n |
2 |
n?m |
2 |
(m+R)(n+R) |
(m+R)(n+R) |
(m+R)(n+R) |