不好意思，最后一步寫錯(cuò)了
求不定積分 ∫(x^2/√a^2-x^2 )dx (a>0)
求不定積分 ∫(x^2/√a^2-x^2 )dx (a>0)
數(shù)學(xué)人氣：555 ℃時(shí)間：2020-05-20 19:04:14
優(yōu)質(zhì)解答
不好意思，最后一步寫錯(cuò)了我來(lái)回答
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