(1) 2+3+4+..n = (n-1)(n+2)/2≥200
(n-1)(n+2)≥400
n^2 + n ≥402
n≥20
n=19時(shí)一起擺了189顆子（此處擺黑子18顆）,后面繼續(xù)擺11顆黑子便是200顆珠子
所以黑子有1+2+..+18 + 11 = 182
(2) 設(shè)A玩具x個(gè),B玩具價(jià)格是b元(b＜25,為整數(shù))
25x + (x - 2)b = 280
若x=2,則花錢為50,矛盾
b = (280-25x)/(x-2)
280＞25x
x＜11.2
3≤x≤11
又b≤24
(280-25x)/(x-2)≤24
280 - 25x≤24x - 48
x≥6.69
x≥7
7≤x≤11
x = 7
b = (280-25x)/(x-2) = 21
x = 8
b = (280-25x)/(x-2) = 13.3
x = 9
b = (280-25x)/(x-2) = 7.8
x = 10
b = (280-25x)/(x-2) = 3.75
x = 11
b = (280-25x)/(x-2) = 0.555
由于b是整數(shù),所以b = 21,x = 7