a²+a-2=6,求2a²-a+1的值
a²+a-2=6,求2a²-a+1的值
數(shù)學(xué)人氣：903 ℃時(shí)間：2020-09-11 17:03:46
優(yōu)質(zhì)解答
解a²+a-2=6即a²+a=82a²-a+1=2（a²+a）-3a+1=2*8-3a+1=17-3a由a²+a-8=0即a=（-1+√33）/2或a=（-1-√33）/2即2a²-a+1=17-3a=17-3*（-1+√33）/2=17+3/2-3√33/2=37/2-3√33/2或2a²...
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