∵a=e^lna
∴y=a^x=(e^(lna))^x=(e^x)^lna
以上復(fù)合函數(shù)求導(dǎo)y‘=lna*(e^x)^(lna-1)*e^x=lna*(e^x)^lna=lna*(e^lna)^x=lna*a^x
y=a^x的導(dǎo)數(shù)為y’=lna*a^x可以當(dāng)做公式記憶,以上是推導(dǎo)過程.
y＝a∧x,他的導(dǎo)數(shù)是什么?
y＝a∧x,他的導(dǎo)數(shù)是什么?
數(shù)學(xué)人氣：849 ℃時間：2020-06-05 21:08:23
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