1.設(shè)點m(xo,yo)在h(x)上
則m關(guān)于(0,1)的對稱點n(-xo,2-yo)在f(x)上
令-xo=x,2-yo=y,則xo=-x,yo=2-y
又yo=xo＋1/xo＋2,則2-y=-x＋1/-x＋2=x-1/x-2,f(x)=y=x-3/x-2
2.∵f'(x)=1/x-2xa^2＋a
f''(x)=-1/x^2-2a^2
∴f'(x)在(0,＋∞)上遞減
要使f(x)在(1,＋∞)上單調(diào)遞減,即要使f'(1)≤0
又f'(1)=-a^2＋a＋1=-(a-1/2)^2＋5/4
∴(a-1/2)^2≥5/4,得a≥(√5＋1)/2或a≤(1-√5)/2