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  • [sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]

    [sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]
    數(shù)學(xué)人氣:119 ℃時(shí)間:2020-04-02 00:57:31
    優(yōu)質(zhì)解答
    sin(540-x)cos(360-x) / tan(900-x)tan(450-x)tan(810-x)sin(-x)
    = sin(180-x)cos(-x) / tan(180-x)tan(90-x)tan(90-x)sin(-x)
    = - sin(x)cos(x)tan(x)tan(x)cos(180-x) / sin(180-x)sin(x)
    = cos^2(x)tan^2(x) / sin(x)
    = sinx
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