4x²y-{6xy-2(4xy-2)-x²y}+1
=4x²y-(6xy-8xy+4-x²y)+1
=4x²y-6xy+8xy-4+x²y+1
=5x²y+2xy-3
=5*(-2分之1)²*1+2*(-2分之1)*1-3
=4分之5-1-3
=4分之5-4
=4分之5-4分之16
=-4分之11
=-2又4分之34x的平方Y(jié)-{6xy-2(4xy-2)-x的平方y(tǒng)}+1麻煩用初一的格式，我加分用的都是初一的格式，你仔細(xì)看看，有什么地方不懂的可以追問(wèn)！4x的平方Y(jié)-{6xy-2(4xy-2)-x的平方y(tǒng)}+1再算下，你這個(gè)我沒(méi)看懂，答案4x²y-{6xy-2(4xy-2)-x²y}+1 先去掉小括號(hào)=4x²y-(6xy-8xy+4-x²y)+1再去掉中括號(hào)=4x²y-6xy+8xy-4+x²y+1合并同類項(xiàng)=5x²y+2xy-3 代入數(shù)據(jù)=5×(-2分之1)²×1+2×(-2分之1)×1-3=4分之5-1-3=4分之5-4=4分之5-4分之16=-4分之11=-2又4分之3