Step 1:第n項 等于 1/(3+(2n-1))*((2n-1-3)/2-1)/2 = 1/(n^2+2)
Step 2:1/(n^2+2) < 1/ (n^2-1)
Step 3:1/ (n^2-1)
1/3+1/(3+3)+1/(3+3+5)+1/(3+3+5+7)+1/(3+3+5+7+9)+.+1/(3+3+5+7+.+2n-1)
1/3+1/(3+3)+1/(3+3+5)+1/(3+3+5+7)+1/(3+3+5+7+9)+.+1/(3+3+5+7+.+2n-1)
數(shù)學(xué)人氣：636 ℃時間：2020-04-24 01:13:00
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