Mg:1g
Zn:0.37g
Fe:0.43g
需要過程請追問...
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Mg + 2HCl = MgCl2 + H2
24 2
12g X
24X = 2*12g
解得X=1g
Zn + 2HCl = ZnCl2 + H2
65 2
12g Y
65Y = 2*12g
解得Y=0.37g
Fe + 2HCl = FeCl2 + H2
56 2
12g Z
解得Z = 0.43g
過程:在哪里啊????過程:
Mg + 2HCl = MgCl2 + H2
24 2
12g X
24 X = 2*12g
解得X=1g
Zn + 2HCl = ZnCl2 + H2
65 2
12g Y
65Y = 24g
解得Y = 0.37g
Fe + 2HCl = FeCl2 + H2
56 2
12g Z
56Z = 2*12g
解得Z = 0.43g