求下列函數(shù)極值1、y=x^2-2x+3.2、2X^3-3X^2-4.
求下列函數(shù)極值1、y=x^2-2x+3.2、2X^3-3X^2-4.
數(shù)學(xué)人氣：526 ℃時(shí)間：2020-02-03 00:36:39
優(yōu)質(zhì)解答
1、y=x^2-2x+3
對(duì)稱軸為x0=-(-2)/2=1
所以,最小值為
y(1)= 2
2、2X^3-3X^2-4.
對(duì)y求導(dǎo)得
y'=6x²-6x=0
解得x1=1,x2=0
知在(-∞,0)和(1,+∞)上y'>0；在(0,1)上y'
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