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  • PYTHON round

    PYTHON round
    For
    this problem,we'll round an int value up to the next multiple of 10 if
    its rightmost digit is 5 or more,so 15 rounds up to 20.Alternately,
    round down to the previous multiple of 10 if its rightmost digit is less
    than 5,so 12 rounds down to 10.Given 3 ints,a b c,return the sum of
    their rounded values.To avoid code repetition,write a separate helper
    "def round10(num):" and call it 3 times.
    Example Output:round_sum(16,17,18) → 60round_sum(12,13,14) → 30round_sum(6,4,4) → 10
    英語人氣:926 ℃時間:2020-09-14 18:12:31
    優(yōu)質(zhì)解答
    $ pythonPython 2.7.3 (default, Jan  2 2013, 16:53:07) [GCC 4.7.2] on linux2Type "help", "copyright", "cre...能不能解析下。我剛剛接觸對于語法不太熟悉。map(func, iterable) 對iterable里的每個元素調(diào)用func函數(shù), 返回值組成新的列表
    # usage loop
    summary = 0
    for item in iterable:
        summary += round(item, -1)
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