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  • ①如果x+ 1/x =3,則 x²/x⁴+x²+1 的值為_________.

    ①如果x+ 1/x =3,則 x²/x⁴+x²+1 的值為_________.
    ①如果x+ 1/x =3,則 x²/x⁴+x²+1 的值為_________.
    ②計算:x+2y+ 4y²/x−2y − 4x²y /x²−4y²
    ③計算:1 /(x+1)(x+2) + 1 /(x+2)(x+3) + 1/ (x+3)(x+4) + 1 /(x+4)(x+5)
    ④試用含字母n的等式表示
    1/ 6 =1 /2×3 =1 /2 − 1/ 3 ,1 /12 =1 /3×4 =1/ 3 − 1/ 4 ,1/20 =1/ 4×5 =1/4 − 1 /5 的規(guī)律(n表示正整數(shù)).
    ⑤計算:1 /(x−2)(x−3) − 2 /(x−1)(x−3) + 1/(x−1)(x−2)
    數(shù)學(xué)人氣:571 ℃時間:2020-04-08 00:57:03
    優(yōu)質(zhì)解答
    1.
    x²/(x⁴+x²+1)
    =1/(x²+ 1+1/x²) /分子分母同除以x²
    =1/[(x+ 1/x)²-1]
    =1/(3²-1)
    =1/8
    2.
    x+2y+4y²/(x-2y) -4x²y/(x²-4y²)
    =[(x+2y)(x-2y)+4y²]/(x-2y)- 4x²y/[(x+2y)(x-2y)]
    =(x²-4y²+4y²)/(x-2y) -4x²y/[(x+2y)(x-2y)]
    =x²/(x-2y) -4x²y/[(x+2y)(x-2y)]
    =[x²(x+2y)-4x²y]/[(x+2y)(x-2y)]
    =x²(x+2y-4y)/[(x+2y)(x-2y)]
    =x²(x-2y)/[(x+2y)(x-2y)]
    =x²/(x+2y)
    3.
    1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+1/[(x+3)(x+4)]+1/[(x+4)(x+5)]
    =1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+1/(x+4)-1/(x+5)
    =1/(x+1) -1/(x+5)
    4.
    規(guī)律:1/[n(n+1)]=1/n -1/(n+1) (n∈N+)
    5.
    1/[(x-2)(x-3)]-2/[(x-1)(x-3)]+1/[(x-1)(x-2)]
    =1/(x-2)-1/(x-3) -[1/(x-1)-1/(x-3)]+1/(x-1)-1/(x-2)
    =1/(x-2) -1/(x-3) -1/(x-1) +1/(x-3) +1/(x-1) -1/(x-2)
    =0
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