x^2+x-|=0
x^2=1-x
所以
x^3-x^2-3x+7
=x(1-x)-1+x-3x+7
=x-x^2-2x+6
=-x^2-x+6
=-(x^2+x-1)+5
=-0+5
=5已知x^3-16x^2+mx-n除以x^2-2x+3所得的余式為-18x+15，求m、n的值。求過程，謝謝