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  • lim(1/x^2 - cot^2 x ) (x趨近于0) 用洛必達法定則

    lim(1/x^2 - cot^2 x ) (x趨近于0) 用洛必達法定則
    數(shù)學人氣:189 ℃時間:2020-05-13 21:43:54
    優(yōu)質解答
    原式=lim(1/x^2-cos^2x/sin^2x)
    =lim(sin^2x-x^2*cos^2x)/(x^2*sin^2x)
    =lim(sin^2x-x^2*cos^2x)/(x^4)
    =lim[cos^2x(tan^2x-x^2)]/x^4
    =lim(tan^2x-x^2)/x^4
    =lim(2tanx*sec^2x-2x)/4x^3
    =lim(sec^4x+2sec^2x*tan^2x-1)/6x^2
    =lim(sec^4x-1)/6x^2+lim(2tan^2x*sec^2x)/6^2x
    =lim[(sec^2x+1)(sec^2x-1)]/6x^2+1/3
    =lim(sec^2x+1)*tan^2x/6x^2+1/3
    =lim(sec^2x+1)/6+1/3
    =1/3+1/3
    =2/3
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