cos1°+cos2°+cos3°+……+cos180°
=(cos1°+cos179°)+(cos2°+cos178°)+(cos3°+cos177°)+……+(cos89°+cos91°)+cos90°+cos180°
=(cos1°-cos1°)+(cos2°-cos2°)+(cos3°-cos3°)+……(cos89°-cos89°)+cos90°-cos0°
=0-1
=-1
cos1°+cos2°+cos3°+...+cos180°的值為?到底是0還是-1?
cos1°+cos2°+cos3°+...+cos180°的值為?到底是0還是-1?
數(shù)學(xué)人氣：169 ℃時間：2020-06-12 08:48:25
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