求如何將（y-0.5）^ 2=x^2+y^2-xy化簡成y=2+(x-1)+3/[4(x-1)],
求如何將（y-0.5）^ 2=x^2+y^2-xy化簡成y=2+(x-1)+3/[4(x-1)],
數(shù)學(xué)人氣：175 ℃時(shí)間：2020-02-06 04:25:29
優(yōu)質(zhì)解答
原式去括號(hào)得：y²-y+0.25=x²+y²-xy移項(xiàng)化簡得：(x-1)y=x²- (1/4)所以：y=[x²- (1/4)]/(x-1)=[(x²-1)+(3/4)]/(x-1)=x+1+ 3/[4(x-1)]=2+(x-1) + 3/[4(x-1)]
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