(1)2/5x^2y^3*(—5/16xyz^2)
=-1/8x^3y^4z^2;
(2)(—4x^2y)*(—x^2y^2)*(1/2y^3)
=2x^4y^6;
(3)(—1/2ab^2c)2*(—1/3abc^2)3*912a^3b)
題目有問題吧
(4)(—3a^n+1b^n)*(1/3ab)*(—a^2c)
=a^(n+1+1+2)b^(n+1)c
=a^(n+4)b^(n+1)c;
很高興為您解答,skyhunter002為您答疑解惑
如果本題有什么不明白可以追問,
計(jì)算:(1)2/5x^2y^3*(—5/16xyz^2) (2)(—4x^2y)*(—x^2y^2)*(1/2y^3)
計(jì)算:(1)2/5x^2y^3*(—5/16xyz^2) (2)(—4x^2y)*(—x^2y^2)*(1/2y^3)
(3)(—1/2ab^2c)2*(—1/3abc^2)3*912a^3b)
(4)(—3a^n+1b^n)*(1/3ab)*(—a^2c)
(3)(—1/2ab^2c)2*(—1/3abc^2)3*912a^3b)
(4)(—3a^n+1b^n)*(1/3ab)*(—a^2c)
數(shù)學(xué)人氣:902 ℃時(shí)間:2020-02-05 14:07:58
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