1 y=(4x^+8x+13)/(6x+6)=(2/3((x+1)+3/(2(x+1))>=2 最小值2
2 y=(x^2-x)/(x^2-x+1) 無
1.求y=(4x^+8x+13)/(6x+6)的最小值
1.求y=(4x^+8x+13)/(6x+6)的最小值
2.求函數(shù)y=(x^2-x)/(x^2-x+1)的最小值
2.求函數(shù)y=(x^2-x)/(x^2-x+1)的最小值
數(shù)學人氣：101 ℃時間：2020-09-09 09:25:10
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